∫3x3+3x+1x2(x2+3)dx\int\frac{3x^3+3x+1}{x^2\left(x^2+3\right)}dx∫x2(x2+3)3x3+3x+1dx
(1.78−1.68)\left(1.78-1.68\right)(1.78−1.68)
sin(θ)1+cos(θ )\frac{\sin\left(\theta\right)}{1+\cos\left(\theta\:\right)}1+cos(θ)sin(θ)
1(3x−2)≤9\frac{1}{\left(3x-2\right)}\le9(3x−2)1≤9
3x=25−x\frac{3}{x}=\frac{2}{5-x}x3=5−x2
18x33+18y3\frac{1}{8}x^{33}+\frac{1}{8}y^381x33+81y3
ddx(x+lnx)\frac{d}{dx}\left(\sqrt{x}+lnx\right)dxd(x+lnx)
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