$4x^2+8x+16=13$
$26+y\:\le-18$
$\int\left(\frac{\left(x-1\right)}{\left(3x+4\right)^2}\right)dx$
$x-21=6$
$b^2+9b+14$
$3x^2-28x+25=8x^2-43x+43$
$\lim_{x\to-5}\left(\frac{x^2+3x-10}{3x^2+15x+25}\right)$
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