$\frac{dk}{dt}=\left[k^2+\left(40k\right)+1\right]$
$\int\frac{x^3}{\left(4-x^4\right)^2}dx$
$46,5\cdot5,9$
$\left(9\sqrt{5x^5}\right)\left(7\sqrt{5x}\right)$
$9+9\cos x=6\sin^2x$
$2x+9\ge6x$
$2\log_{3}5=\log_{3}\square$
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