$6.\left\{3.\left\{9+4\left(5.3-9\right)\right\}-3.\left(40-8\right)\right\}$
$\left(q^0q^5\right)^{-1}$
$6x-y=3$
$\sec^2t+\csc^2t=\csc^2t\cdot\sec^2t$
$\int100^{\frac{1}{3}}dx$
$-17x^2+22x^2$
$\left(x+9\right)=15$
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