$\left(e^x+1\right)^3e^{-x}dy=\left(e^y+1\right)^2e^{-y}dx$
$a-5a+8a-7a+4a$
$tan^2x-1=-sec^2x\left(cos2x\right)$
$\left(x^3+5\right)\left(x+7\right)$
$\:-3\cdot5+7-3\cdot4-10\cdot2$
$24.95+4.95$
$16a^2+24b$
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