$\left(3a\right)\:+\left(1\right)^2$
$\frac{4x^2-3}{2x}$
$\left(6-8a+6a^2\right)^2$
$12x^2-24x+8$
$1\left(x\right)=2x^2+5x^3$
$10x^{\left[2\right]}-24x=0$
$5\cdot1-1$
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