limx→0(1+5h)1h\lim_{x\to0}\left(1+5h\right)^{\frac{1}{h}}x→0lim(1+5h)h1
4x2−3x−14x^2-3x-14x2−3x−1
15∫x2sinxdx\frac{1}{5}\int x^2sinxdx51∫x2sinxdx
f(x)=116+4xf\left(x\right)=\frac{1}{16+4x}f(x)=16+4x1
2x+1x+3>3\frac{2x+1}{x+3}>3x+32x+1>3
∫02(tan5(x)⋅sec2(x))dx\int_0^2\left(\tan^5\left(x\right)\cdot\sec^2\left(x\right)\right)dx∫02(tan5(x)⋅sec2(x))dx
x+12=17x+12=17x+12=17
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