$\frac{x^2+x+6}{x^2+4}$
$y'+10xy=3x$
$\left(3m\:+\:1\right)^2$
$10\:x\:\left(-3\right)$
$\left(\frac{2}{3}a^3b^4c^{-3}+11ab^2\right)^2$
$\int\left(x\cdot\left(3x-2\right)^{0.5}\right)dx$
$3x+8=-19$
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