$\frac{\left(2x^2\right)^2}{20x^3}$
$\left(8x^3y^{-3}\right)^{\frac{-2}{3}}\left(x^{-8}y^{-4}\right)^{\frac{3}{4}}$
$\left(ab+7b\right)^2$
$13x^2y^32$
$\int_0^{\frac{\pi}{3}}\left(\frac{1}{\sqrt{64-x^2}}\right)dx$
$xy^2y'=x+8$
$\left(-6x^2\right)\left(-9x^3\right)$
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