$\frac{dy}{dx}=\left(\sec\left(x\right)\right)^2\left(1-3y\right)$
$4350-2900-800-500$
$x^4+625+x^4$
$\left(3a^3-3b^2\right)\left(3a^3+3b^2\right)$
$8a^2-24xy+18y^2$
$\int tan^3\left(4x\right)\cdot sec^2\left(4x\right)dx$
$x^2-x-3;\:x=-3;\:$
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