$6x^2+13x+6=0$
$x4+4<0$
$598-31$
$16x^{2-40x+25}$
$\cos\left(x\right).\sin\left(x\right)=\tan\left(x\right)$
$\lim_{x\to\infty}\left(\frac{1-\cos\left(x\right)}{x^2+x}\right)$
$\frac{16y^5x^4}{8x^2y^2}$
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