$8x^2-4x-5=0$
$\left(y-4\right)\left(y-7\right)$
$2\left(1\right)^4-32$
$2\left(56\right)-7$
$\frac{d}{dx}y\:=\:x\sqrt[3]{1\:+\:x^2}.$
$\frac{dy}{dx}=6tan\left(3y\right)$
$3\left(x^2+7\right)-2\left(x^2+3\right)+\left(x^2+5\right)$
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