$r^2+12r+36$

$\frac{1}{4}x^2+3x-6x^2-\frac{1}{6}x+\frac{2}{3}-\frac{1}{4}$

$\sin\left(2x\right)+\sin\left(x\right)=6\cos\left(x\right)+3$

$1+\left(x^{\frac{1}{4}}\right)^2$

$\left(2sinx-cosx\right)^2+3cos^2x=4-4sinxcosx$

$sin^2\left(x\right)\:\frac{sin\left(x\right)cos\left(x\right)}{tan\left(x\right)}$

$64-x^2$