$\lim_{x\to1}\left(\frac{x^3-3x-4}{x^2-3x+2}\right)$
$\frac{3x+1}{x-2}\:=\:2$
$14-\left(18-2\right)-\left(-10-3\right)$
$5\left(a+7\right)$
$\lim_{x\to\infty}\left(e^{\left(-2x\right)}ln\left(5x^2\right)\right)$
$\left(\left(2\right)\left(-3\right)\left(4\right)\right)^2$
$l=1+\frac{1}{1+l}$
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