$\left(\frac{1}{3}x+2y\right)\left(\frac{1}{3}x-6y\right)$
$cos\left(x-y+5\right)dx-dy=0$
$x^3+x^2+2x$
$-15\::\:-5$
$95^2+23z^6+144$
$y'=\frac{\left(x\cdot e^x\right)}{y\sqrt{1+y^2}}$
$\left(a^2-2b^3\right)\left(a^2+2b^3\right)$
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