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Exercise

$\int\frac{x^5}{e^{4-3x}}dx$

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Final answer to the exercise

$\frac{1}{3}e^{\left(-4+3x\right)}x^5-\frac{40}{243}e^{\left(-4+3x\right)}+\frac{40}{81}xe^{\left(-4+3x\right)}-\frac{20}{27}x^{2}e^{\left(-4+3x\right)}+\frac{20}{27}x^{3}e^{\left(-4+3x\right)}-\frac{5}{9}x^{4}e^{\left(-4+3x\right)}+C_0$

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  • Integrate by partial fractions
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