$\frac{z}{6}-14=3$
$9x-7+x+8$
$\left(a-\frac{2}{7}\right)^3$
$\lim_{x\to-4}\sqrt[3]{\frac{3-4x}{2-x}}$
$\frac{1}{x-1}\ge-2$
$tan^2x-8tanx+13=0$
$6c^2-13c+3$
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