$2a=4$
$\lim_{x\to\infty}\left(\frac{1}{x^3+2x-3}\right)$
$\int\left(\frac{\left(x^4\right)}{x^2-1}\right)dx$
$3\left(\tan\left(225\right)^2\right)+\cot2\left(225\right)-3=0$
$70.292\cdot109$
$\frac{x}{\left(4+x\right)^2}$
$x ^ { 2 } + y ^ { 3 } = 25$
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