$y=\frac{3^{x+1}}{\cos x}$
$\left(+3\right)+\left(-6\right)-\left(+7\right)-\left(-5\right)$
$4^{x^2}=32$
$\int\frac{4}{x\sqrt{9-4x^2}}dx$
$\frac{x^2-9}{9}$
$4x-13\le2x+15$
$\int_0^2\left(2xe^{-2x}\right)dx$
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