$\frac{-3}{5}tan2t$
$y=\frac{x}{x^3-1}$
$\frac{dy}{dx}=\frac{x^2-6x+2}{y-2}$
$\left(x+3\right)^2-\left(x-5\right)^2$
$14\cdot\infty$
$\frac{a^2b^4.\left(-a^4\right)^4}{-a^2b^2}$
$\left|25-3\right|$
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