$\frac{\sqrt[5]{x^2}}{x}$
$\lim\:_{x\to\:\:25}\frac{x-25}{\sqrt{x}-5}$
$\lim_{x\to0}\left(\frac{e^{\left(2x\right)}}{x^2}\right)$
$\left(xy-3-3y+x\right)dy=\left(xy-2+2y-x\right)dx$
$+3xy+8xy-2xy$
$\left(3x^4+5x^3-7x+2\right)-\left(3x^4-6x^3-x+5\right)$
$\left(-7+2\right)\left(6+3-2\right)$
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