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f(x)=(x^2)/((64+x^2)^2)−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

∫x2(64+x2)2dx\int\frac{x^2}{\left(64+x^2\right)^2}dx

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Final answer to the exercise

18arctan⁡(x8)−15ln⁡∣64+x2∣+110ln⁡∣864+x2∣+5−2(64+x2)−116arctan⁡(x8)+−x2(64+x2)+C1\frac{1}{8}\arctan\left(\frac{x}{8}\right)-\frac{1}{5}\ln\left|\sqrt{64+x^2}\right|+\frac{1}{10}\ln\left|\frac{8}{\sqrt{64+x^2}}\right|+\frac{5}{-2\left(64+x^2\right)}-\frac{1}{16}\arctan\left(\frac{x}{8}\right)+\frac{-x}{2\left(64+x^2\right)}+C_1

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∫x2(64+x2)2 dx
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