Find the integral $\int\frac{x^2+x+3}{x-2}dx$

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Learn how to solve problems step by step online. Find the integral int((x^2+x+3)/(x-2))dx. Divide x^2+x+3 by x-2. Resulting polynomial. Expand the integral \int\left(x+3+\frac{9}{x-2}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int xdx results in: \frac{1}{2}x^2.