$3x+5\cdot4x+8$
$\frac{20a^3c^4d^2}{-5a^3c^3}$
$3x+4+\frac{x}{4}<\frac{5x}{2}+2$
$2\sin^2\left(x\right)+1=3sinx$
$\frac{1}{5-x},c=1$
$6x^2+19x-10=0$
$3x^3-\frac{1}{2}x^2-5x\cdot2x-3$
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