$\frac{8^{10}}{8^3}$
$\left(2x^2\:+\:4x\:-\:3\right)\:\left(x^2\:-\:7x\:+\:1\right)$
$4x^2-12x+2$
$x^2+12x+12y+96=0$
$2x+\frac{-6x+12}{x^2-4}$
$a^2b-a^2b-3a^2$
$\frac{x^3-4x^2-3x+2}{x-2}$
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