$\left(\left[\frac{4}{3}\right]x^{1-y}-8y^{8-x}\right)^2$
$x^2=\frac{6x+36}{2}$
$\frac{d^2}{dx^2}\left(\frac{3x-4}{2x+3}\right)$
$24a^2xy^3-36x^2y^4$
$\lim_{x\to\infty}\left(\frac{10x+15}{2x^4+7x^2+26x}\right)$
$\left(-8-7x\right)^2$
$\frac{x^3}{4-x}$
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