$\int\frac{1}{4}\left(sin\left(x\right)\right)^5dx$
$sec^2x-sin^2xsec^2x=1$
$18my^2\left(x-3mx^2+2\right)$
$\left(6a^2b^3+5x^2\right)^2$
$\left(\frac{4}{5}x-\frac{7}{3}y\right)^2$
$3+4-5\cdot3+\frac{9}{3}$
$\int e^5^xdx$
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