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$\int\frac{x+2}{x^3\left(x^2+x+2\right)\left(3-x\right)}dx$

Final answer to the exercise

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Other solved exercises

$\frac{1}{y}dy=\frac{1}{1+x}dx$

$x^2+24x+143=0$

$12x^2-4+5$

$4x-2.x-3$

$-497\cdot100$

$a:184\:c:513$

$\left(2a-3b+c\right)\left(2a+3b-c\right)$
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