$y=\sqrt{25+\left(5\tan\left(x\right)\right)^2}$
$\lim_{x\to1}\frac{3x+2}{4x-5}$
$\frac{2x^4-2x^3}{x+1}$
$\left(4x+3\right)^3$
$\sin\left(3x\right)\cdot3x\cos\left(3x\right)$
$4\cos\left(x\right)+3=6$
$\frac{2x+14}{x^2+15x+56}.\frac{x^2+3x-40}{6x}$
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