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$10x^2-9x+2$
$\left(3^2\right)^8$
$-x^3-2x^2+1$
$\left(7\right)-\left(5\right)+\left(-5\right)+\left(-10\right)-\left(-7\right)+\left(4\right)$
$b=\frac{n\left(n-1\right)}{4}$
$x+12>3x+20$
$4+-5+-1+-8$
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