$9x^2+24x-48$
$3x-7y=-3y+7x$
$\left(5x^{2}-\frac{4}{x^{3}}\right)^{4}$
$-5\left(-4\right)^2\:-\:\left(-18\right)$
$7x^2-5x-150$
$(\frac{2}{5}x^3+\frac{9}{4}y^2)\:(\frac{2}{5}x^3-\frac{9}{4}y^2)$
$12n^4+6n^3-3n^2$
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