$\lim_{x\to-2}\left(\frac{\sqrt{x+4}-2}{x}\right)$
$\lim_{x\to\infty}\left(\frac{1}{\sqrt{2\:x^2+2x+1}}\right)$
$\sqrt[3]{m^2}n^5$
$\left(x+6\right)\left(3x-5\right)$
$\:2^2+234+4^2$
$\frac{sec^2x\:-\:\cos^2x}{\tan^2x}$
$\cos10\cdot\left(\tan10+1\right)$
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