$4xe3+4x$
$\cos\left(x\right)^2=\left(1-\sin\left(x\right)^2\right)\left(1+\tan\left(x\right)^2\right)$
$x^4-30x+3\::\:x-3$
$\left(-38\right)\left(-25\right)$
$3\ln\left(y\right)dy=xe^xdx$
$x^2+9x-10=0$
$3x^2-4^2$
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