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$\int\frac{9x^2-16x+4}{x^3-3x^2-2x}dx$

Final answer to the exercise

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Other solved exercises

$2an^4+16an^2-32a$

$6a+14$

$x^2+18x-4=0$

$1x^2-6x+6$

$\left(\frac{x^2}{9}-\frac{1}{x^2}\right)^4$

$\frac{5x^2+7x-3}{x+3}$

$\frac{1.25}{0.0249066144}$
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