$\lim_{x\to0}\left(\frac{2x\cdot\cos\left(3x\right)-sen\left(3x\right)}{4x^3}\right)$
$6=x+8$
$\frac{2x+6}{x^2+8x+15}$
$2,2222222222222223+1,6$
$\lim_{x\to0}\left(\frac{\sin^3\left(2x\right)\left(2x\right)}{2x^3}\right)$
$4sin2\:x+3cosxsinx=0$
$-9.1\cdot\left(-4.5\right)$
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