$4\left(t\right)x\frac{dx}{dt}=x^2+1$
$\left(3w-7z\right)^2$
$5a\cdot5c$
$\int\left(\left(2x^2-7\right)\left(e^{3x}\right)\right)dx$
$-4x<16$
$5.2+7.1+3.9+4.8+4.25+5.75$
$\frac{4x}{x^4+2x^2+1}$
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