$x^2+11x-5=0$
$\left(a^3+1\right)\left(4a-1\right)\:\:$
$\left(-3x^2y^4z^5\right)\cdot\left(-2x^4yz^2\right)$
$\frac{dy}{dx}=\frac{2x}{y},\:y\left(1\right)=1$
$t'\left(6t^2+10t+4\right)$
$x^2+11x+11=0$
$5\cdot3\cdot7$
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