$\int_0^{\frac{\pi}{6}}\left(secx-cosx\right)^2dx$
$25x^2+\frac{100}{7}+\frac{1}{49}$
$3\left(11\right)^4-3\left(11\right)^3-\left(9\right)^2+3\left(9\right)-1\:$
$x^2dy+\left(2xy-3y^2\right)dx=0$
$3x-3x+1$
$3x-6\le x+10$
$-7x-18=-11$
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