$\int\sin\left(3t\right)dt$
$y=\ln\left(6-2x\right)$
$720.5\frac{1}{3}$
$\left(m^3+4m^2+5m+2\right)\left(m-2\right)$
$121x^{2\:}-625$
$\frac{\left(\cot\left(y\right)\:-\:\tan\left(y\right)\right)}{\left(cos\left(y\right)+sin\left(y\right)\right)}$
$x^2+40x+150$
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