$\left(-9\right)\left(-6\right)\left(-4\right)$
$\sin\left(x+1\right)\tan\left(x\right)-\sec\left(x\right)$
$-4x\sin\left(2x\right)+2\cos\left(2x\right)-2x+4$
$\lim_{x\to2}\left(\frac{x^2+x-6}{2x^2+3x-10}\right)$
$5x^2-15x+10$
$\left(-27\right).18$
$4\left(1\right)^3-4\left(1\right)^2+9\left(1\right)-9$
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