$2\cos\left(x\right)^2-\sec\left(x\right)^2=\cos\left(2x\right)-\tan\left(x\right)^2$
$2^{-3}\cdot2^5$
$\int\frac{1}{\left(x+2\right)\left(2x+3\right)}dx$
$1.04^8$
$10y+1<-9$
$\left(2g^3\right)^2$
$\left(4x-11y\right)\left(4x+11y\right)$
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