$\frac{dy}{dx}=2\cos\left(x\right)-y\tan\left(x\right)$
$5x>10$
$y'\:=\:\left(-x\:-\:1\right)\:y^3$
$\int\left(\tan\left(\frac{x}{2}\right)\sec\left(\frac{x}{2}\right)^2\right)dx$
$\left(4b-10\right)\left(4b+10\right)$
$-3-\left(-1\right)$
$-15-\left(-2+9\right)$
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