$\frac{dy}{dx}=\frac{\left(lnx\right)^3}{xy^2}$
$\tan^2b-2\tan^2b\cdot\sec^2b+\sec^4b$
$\int\frac{x+4}{x^3+4x^2+4x}dx$
$3.8-6.2$
$6x^3-18x-12$
$\int\frac{x}{\sqrt{x+a}}dx$
$-8w+1-7w$
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