$\frac{\left(-\frac{2}{x}\right)}{\left(\frac{4x^3}{5}\right)}$
$\int\left(2x\left(x+1\right)^5\right)dx$
$\frac{4^2}{4^{-3}}$
$-10n+10n=0$
$\int tan6\left(x\right)dx$
$\lim_{x\to0}\left(2+x^5ln\left(x\right)\right)$
$2e^{\frac{-\infty}{2}}-2\infty$
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