$1a^2+30ab+169b^2$

$\left(-4x^3+6\right)\left(4x^3+6\right)$

$\frac{\left(\frac{-4}{3}\right)-\left(\frac{3}{4}\right)}{1+\left(\frac{-4}{3}\right)\left(\frac{3}{4}\right)}$

$\left(1\right)^2-2\left(1\right)+2$

$\frac{1}{\:3\:}x=5$

$11.20^2$

$\lim_{k\to1}\left(\frac{k^{\frac{4}{3\:}}+7}{\left(k+1\right)^{\frac{4}{3}}+7}\right)$