$\frac{dy}{dx}+\frac{\left(6y\right)}{x+4}=\left(x+4\right)^8$

$-3x^2-12x-15$

$x^2-2x+10=0$

$\frac{\cot\left(u\right)-1}{\cot\left(u\right)+1}$

$\left(a^2+3b^2\right)^3$

$\int\frac{\left(2x^2+x+2\right)}{\left(x-1\right)\left(x^2+4\right)}dx$

$\left(9-6y\right)\left(9+6y\right)$