$\frac{x^2+4x+4}{2x-4}$
$-\left(\frac{28}{4}\right)$
$\frac{10^2-\left(100+8^2\right)}{2^3}$
$3^6:3^4$
$\left(+4\right)-\left(+5+7\right)-\left(-2\right)-\left(+3\right)-\left(+4\right)$
$-5\left(27+23\right)\left(-3\right)$
$\left(n-3\right)\left(n\right)-4$
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