$\int_1^5\left(\frac{x-1}{x^3+x}\right)dx$
$\frac{x^3+x^2+2x+1}{x^4+3x^2+3}$
$\left(8\cdot m\right)+\left(8\cdot4\right)$
$\left(5bc^2-4x\right)^2$
$7x^2-x+10$
$-7+15-8+25-17-6-18+30+0$
$y=3\cdot y$
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