$\sqrt{\left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right)}$
$\frac{x^4}{-4}+4x^2-16$
$\left|-3\cdot4\right|\cdot\left(-5\right)$
$4\left(-1\right)\left(-2\right)^2-3$
$2x^5-3x^3$
$\:\frac{cos^2x+tan^2x-1}{sin^2x}=tan^2x$
$\int\frac{-3+x}{x^2+2-3x}dx$
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