$5x^2\le x+10$
$\frac{\left(x^3-x+3\right)}{\left(x^2+x-2\right)}$
$y=\frac{\left(x+3\right)^4}{\left(x-3\right)^{-3}}$
$m^2+5m-6$
$10\cdot10^{10}$
$\sqrt[10]{0}$
$-3a^2b\left(5a^3bc^2-10ab^5c\right)$
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